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As a follow-up: Given that VAL is a string in this case, how can we retrieve the underlying boolean value of 0 or 1?
Thanks!
Scott
From: Tech-talk <tech-talk-bounces at aps.anl.gov> on behalf of Feister, Scott via Tech-talk <tech-talk at aps.anl.gov>
Sent: Wednesday, August 11, 2021 11:54 AM To: tech-talk at aps.anl.gov <tech-talk at aps.anl.gov> Subject: Simple binary input question about RVAL?
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Hi EPICS users,
This is a very basic question regarding getting started with binary inputs, and the purpose of RVAL. (As an aside, perhaps we should anyone provide an example for a binary input (bi) similar to the “temperature:water” (ai) example from the Getting Started guide under “Test EPICS”, at:
My students and I have been struggling to get a simple binary input working, though I think we’ve got it now. We first tried expanding, in the above Getting Started tutorial, the “test.db” script with:
test.db: “”” record(ai, "temperature:water") { field(DESC, "Water temperature in the fish tank") } record(bi, "isfishy") { field(DESC, "True if the fish tank has fish inside.") } “””
However, “caget isfishy” shows a blank value, and “caput isfishy 0” does not seem to change anything. This perplexed us for a while.
Looking into it further in the user docs, we landed at documentation for the binary input record: https://epics.anl.gov/EpicsDocumentation/AppDevManuals/RecordRef/Recordref-11.html
Then, we tried modifying ZNAM and ONAM such as test.db: “”” record(bi, "isfishy") { field(DESC, "True if the fish tank has fish inside.") field(ZNAM, "False") field(ONAM, "True") } “””
And now we can do “caput isfishy 1” and all “caget isfishy” prints with “True”, as does “caget isfishy.VAL”. However, I noticed that “caget isfishy.RVAL” still gives 0. So here’s my question: Is this zero in RVAL expected even though the Boolean is now True, and why? Thanks!
Scott
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ANJ, 11 Aug 2021 |
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